(3x-140)^1/2=(x/5)^1/2

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Solution for (3x-140)^1/2=(x/5)^1/2 equation: 


x in (-oo:+oo)

((3*x-140)^1)/2 = ((x/5)^1)/2 // - ((x/5)^1)/2

((3*x-140)^1)/2-(((x/5)^1)/2) = 0

(3*x-140)/2+(-1/10)*x = 0

(3*x-140)/2-x/10 = 0

(10*(3*x-140))/(2*10)+(2*(-x))/(2*10) = 0

10*(3*x-140)+2*(-x) = 0

28*x-1400 = 0

(28*x-1400)/(2*10) = 0

(28*x-1400)/(2*10) = 0 // * 2*10

28*x-1400 = 0

28*x-1400 = 0 // + 1400

28*x = 1400 // : 28

x = 1400/28

x = 50

x = 50

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